The kinetic theory of gases states that
The molecules’ translational kinetic energy in n moles of gas is equal to f/2 nRT.
(where f is the ideal gas’s degrees of freedom.)
Furthermore,
We can infer from the two equations that Cv = f/2 R.
There are six degrees of freedom for a polyatomic gas.
Cv = 6/2 R, then
Assuming R = 8.314
Cv = 3 x 8.314
= 24.9 J/mol.K
Therefore, A) 24.9 J/mol.K is the molar specific heat for an ideal polyatomic gas.
Since this is numerical, there is only one right answer.
The kinetic theory of gases states that
The molecules’ translational kinetic energy in n moles of gas is equal to f/2 nRT.
(where f is the ideal gas’s degrees of freedom.)
Furthermore,
We can infer from the two equations that Cv = f/2 R.
There are six degrees of freedom for a polyatomic gas.
Cv = 6/2 R, then
Assuming R = 8.314
Cv = 3 x 8.314
= 24.9 J/mol.K
Therefore, A) 24.9 J/mol.K is the molar specific heat for an ideal polyatomic gas.
Since this is numerical, there is only one right answer.