Generate Quiz 68DC3F4939C7C

The formula for the ratio of retarding force to speed (v) is (6πη r v)/v, or 6πη r.

𝑀𝑎𝑠𝑠/𝑡𝑖𝑚𝑒 = ρ × 𝑉/𝑇 = ρ × 𝐴 × 𝑑/𝑇 = ρ × 𝐴 × 𝑣
where v is velocity, A is area, V is volume, and T is time.
The formula for mass flow per second of fluid is pAv.

The formula for the equation of continuity is A1V1 = A2V2. The mass flow rate through a control volume is constant, according to this equation. Stated differently, the volume of fluid entering the control volume must be equal to the volume of fluid exiting the control volume.

A body is said to be in terminal velocity when the downward (weight) and upward (drag) forces acting on it are equal. This means that the body falls at a constant speed because there is no force acting on it as a result.

“Its density remains constant” is the right response. This is a property of a fluid that cannot be compressed. An incompressible fluid’s density remains constant regardless of temperature or pressure. This indicates that compressing or expanding an incompressible fluid will not alter its volume.

For a sphere with a constant radius ‘r’ traveling through a liquid with a viscosity n, force and velocity are directly proportional to one another, as demonstrated by the Stokes law equation (given below). Therefore, a straight line through the origin must be the graph’s shape.

F = 6πιηv

Drag is a force acting in opposition to the relative motion of any moving object with respect to a surrounding fluid. It is also referred to as air resistance, a type of friction, fluid resistance, another type of friction, or fluid friction in fluid dynamics.

A fluid that is non-viscous, incompressible, and has a constant flow is ideal.

When a fluid is incompressible, its density remains constant regardless of temperature or pressure.
When a fluid exhibits steady flow, its velocity at a specific point in time remains constant.

When a fluid is non-viscous, it cannot withstand shear stress.
No fluid is really ideal in practice. But in some circumstances, a lot of fluids can be roughly described as ideal fluids. Air, for instance, can be roughly described as an ideal fluid at high speeds and low pressures.

An ideal fluid’s characteristics make analysis and modeling a breeze. For this reason, fluid dynamics problems frequently use ideal fluids.

The sum of the static and dynamic pressures remains constant while the water flows through the horizontal tube in a streamline flow.

P + 1/2 (ρv2) = P/2 +1/2 (ρv12)

v1 = √(P/ρ + v2)

The drag force for small objects (like bacteria) moving in a denser medium (like water) is determined by Stokes’ law, which reads Fs = 6πηrv, where r is the object’s radius, η is the fluid viscosity, and v is the object’s velocity.
The drag force and the object’s velocity are exactly proportional. Therefore, the drag force increases as the object’s velocity increases. For drag force, A is not always true.

Height = h = 10 m

Gravitational acceleration = g = 9.8 m/s²

Speed = v =?

The formula

The speed of efflux through the leak can be ascertained by applying Torricelli’s law, which states that the following equation provides the speed of efflux of a fluid through an opening:

v = √2gh

= √2 × 9.8 × 10.

v = 14 m/s

The unit of volume per second is meter3/sec. A three-dimensional figure’s volume, which is expressed in cubic meters, is the amount of space it encloses. A cube with a volume of 10 cubic meters, for instance, would have a volume per second of 10 m3/s.

Fs = 6πrηv is the formula for viscous drag force.

It is evident from the given formula that F is proportional to v for a given object in a fluid, provided that r and η remain constant.

Therefore, the only appropriate relationship is option A.

Options B, C, and D are incorrect.

Torricelli’s Law, which reads as follows: v = √(2gh), where v is the efflux speed, g is the acceleration caused by gravity, and h is the fluid height above the hole, provides the speed of efflux through a small hole in a large tank.

The acceleration due to gravity, or v = g = 9.8 m/s2, is equal to the speed of efflux through the hole, which is 9.8 m/s.
When we enter these values into the equation above, we obtain:
9.8 = √(2gh)
96.04 = 2gh is the result of squaring both sides of the equation.
9.5 meters is equal to 96.04 / (2g) h = 96.04 / (2 x 9.8) h.
As a result, the fluid is 4.9 meters above the hole.

The continuity equation, A1v1 = A2v2, is the product of the pipe’s cross-sectional area and the fluid velocity at any given point along the pipe, and it is constant.

The continuity equation states that an incompressible fluid’s mass flow rate stays constant along a streamline, implying that the cross-sectional area multiplied by the fluid speed also stays constant.

The continuity equation, A1v1 = A2v2, is the product of the pipe’s cross-sectional area and the fluid velocity at any given point along the pipe, and it is constant.

The continuity equation states that an incompressible fluid’s mass flow rate stays constant along a streamline, implying that the cross-sectional area multiplied by the fluid speed also stays constant.

√3P/ρ: This choice is the right formula for a gas’s root mean square velocity. The formula √(3ρ/P), where ρ is the gas’s density and P is its pressure, yields the RMS velocity.

Because the pipe is horizontal, the average height stays constant, meaning that ph=0. Thus, 2P+pv2 = constant is a possible way to express Bernoulli’s equation.

There is only one possible response because it is a numerical question.

All of the fluid’s particles pass through the same point when a fluid moves in a streamline flow, which forms a point shape at the front.

v2=u2+2as

v2=0+2(5)(10)

v2 = 100

v = 10 m/s

There is only one possible response because it is a numerical question.

According to the physics law known as Stokes’ law, the force that prevents a sphere from falling in a viscous fluid is exactly proportional to the sphere’s velocity, radius, and fluid viscosity, or 6πrv.

Blood has almost the same density as water.[PAGE 137, REF PTB]Blood had an average density of 0.994 g/mL ± 0.032 g. Water’s density is commonly measured in grams per milliliter (1 g/ml) or grams per cubic centimeter (1 g/cm3).

According to the ratio 2:3, there are twice as many moles of gas sample 1 (n1) as there are moles of gas sample 2 (n2).

The formula for pressure is force divided by area. Assuming a circle as the base, the area of the needle’s face equals πr2. The area increases four times as a result of the diameter being doubled. As a result, the pressure drops four times. In order to achieve the same length of penetration, four times the pressure that was previously applied should now be applied.