First, we will write the reaction’s balanced equation. This is provided below:
O2 + 2H2 —> 2H2O
We can infer from the above balanced equation that:
2 cm³ of H2 and 1 cm³ of O2 combined to form 2 cm³ of H2O.
We will then identify the excess reactant.
The following is how to obtain this:
Based on the above balanced equation,
Reaction between 1 cm³ of O2 and 2 cm³ of H2.
As a result, 10 cm³ of O2 will react with 10 × 2 = 20 cm³ of H2 = (10 × 2)/1.
Only 20 cm³ of the 50 cm³ of H2 provided is required to react fully with 10 cm³ of O2, according to the calculations above.
Consequently, H2 is the excess reactant (non-limiting reactant) and O2 is the limiting reactant.
Lastly, we will calculate the amount of the excess reactant, or non-limiting reactant, that remains after the reaction.
The following is how to obtain this:
Non-limiting reactant (H2) volume = 50 cm³
20 cm³ is the volume of the non-limiting reactant (H2) that underwent the reaction.
The amount of non-limiting reactant (H2) that is left over is equal to the volume of the non-limiting reactant minus the volume of the non-limiting reactant that reacted.
Remaining volume of non-limiting reactant (H2) = 50 – 20
= 30 cm³
First, we will write the reaction’s balanced equation. This is provided below:
O2 + 2H2 —> 2H2O
We can infer from the above balanced equation that:
2 cm³ of H2 and 1 cm³ of O2 combined to form 2 cm³ of H2O.
We will then identify the excess reactant.
The following is how to obtain this:
Based on the above balanced equation,
Reaction between 1 cm³ of O2 and 2 cm³ of H2.
As a result, 10 cm³ of O2 will react with 10 × 2 = 20 cm³ of H2 = (10 × 2)/1.
Only 20 cm³ of the 50 cm³ of H2 provided is required to react fully with 10 cm³ of O2, according to the calculations above.
Consequently, H2 is the excess reactant (non-limiting reactant) and O2 is the limiting reactant.
Lastly, we will calculate the amount of the excess reactant, or non-limiting reactant, that remains after the reaction.
The following is how to obtain this:
Non-limiting reactant (H2) volume = 50 cm³
20 cm³ is the volume of the non-limiting reactant (H2) that underwent the reaction.
The amount of non-limiting reactant (H2) that is left over is equal to the volume of the non-limiting reactant minus the volume of the non-limiting reactant that reacted.
Remaining volume of non-limiting reactant (H2) = 50 – 20
= 30 cm³