Generate Quiz 6889E72DEB46C

Alkene ozonolysis:

Ozonolysis is the process of employing ozone (O3), a reactive form of oxygen, to oxidatively cleave alkenes or alkynes. The procedure enables double bonds with oxygen to take the place of carbon-carbon double or triple bonds.

On ozonolysis, the third compound yields acetone and propanaldehyde. Thus, the compound shown in Option C will be the reactant.

A positive iodoform test is appropriately indicated by the formation of yellow crystals. The iodoform test produces iodoform (CHI3) as a yellow precipitate when a compound with a methyl ketone or secondary alcohol group reacts with iodine and a base. The presence of the functional groups that the iodoform test is looking for is confirmed by the yellow precipitate, which is frequently seen as yellow crystals.

Aldehydes and ketones with alpha hydrogen (hydrogen adjacent to carbonyl carbon) do not give rise to Cannizzaro’s reaction.

Since formaldehyde lacks α hydrogen, this reaction will occur.

Acetaldehyde cannot go through this reaction because it has three α hydrogens next to the C=O group.

Trimethyl acetaldehyde will undergo this reaction because it has three CH3 groups attached to its α carbon and no α hydrogen.

Because benzaldehyde has a benzyl group on its α carbon, it lacks α hydrogen and will experience this reaction.

Primary alcohols can be oxidized to produce aldehydes. Aldehydes are the initial product of the oxidation of primary alcohols. Carboxylic acids are produced when aldehydes undergo additional oxidation. Option D is therefore the right choice.

Secondary alcohol is created when ketones are reduced. While the other aldehydes undergo reduction to form primary alcohols, formaldehyde undergoes reduction to form methanol.

Through the Cannizzaro reaction, benzyl alcohol was chemically produced in small quantities from benzaldehyde and potassium hydroxide. It is a significant synthetic chemical that is also widely produced throughout nature at modest levels.
The aldehyde does not contain an alpha carbon.

A yellow iodoform precipitate is produced when methyl ketone and iodine are heated together in the presence of sodium hydroxide. Thus, the iodoform test is used to characterize methyl ketones. Methyl ketone is changed into the sodium salt of carboxylic acid in this reaction.