Since the units must be consistent, we must convert the wavelength λ, which is 6600 angstroms, to meters.
1 angstrom (˚A) = 1×10−10 meters.
So, 6600 A˚=6600×10−10 m=6.6×10−7 m
E = hc/λ
E is 3.013×10−19J.
The photon’s energy is about 3×10−19J, rounded to one significant figure.
Since the units must be consistent, we must convert the wavelength λ, which is 6600 angstroms, to meters.
1 angstrom (˚A) = 1×10−10 meters.
So, 6600 A˚=6600×10−10 m=6.6×10−7 m
E = hc/λ
E is 3.013×10−19J.
The photon’s energy is about 3×10−19J, rounded to one significant figure.