The reaction’s balanced chemical equation is provided below.
4Al + 3O2 → 2Al2O3
The molar mass of oxygen gas is 32g, whereas that of aluminum is 27g. According to the equation above, 3×32 = 96, meaning that 96g of oxygen is needed to fully react with 4×27 = 108g of aluminum. So
108g of aluminium → 96g of oxygen
1g of aluminium → (96 / 108) of oxygen
so 27g of aluminium → (96 x 27) / 108 of oxygen = 24g of oxygen
The reaction’s balanced chemical equation is provided below.
4Al + 3O2 → 2Al2O3
The molar mass of oxygen gas is 32g, whereas that of aluminum is 27g. According to the equation above, 3×32 = 96, meaning that 96g of oxygen is needed to fully react with 4×27 = 108g of aluminum. So
108g of aluminium → 96g of oxygen
1g of aluminium → (96 / 108) of oxygen
so 27g of aluminium → (96 x 27) / 108 of oxygen = 24g of oxygen