We’ll apply the following equation:
h = (1/2)gt2
where g is the acceleration caused by gravity (about 9.8 m/s² on the surface of the Earth), t is the time it took to reach the ground, and h is the vertical distance fallen (in this case, the height of the cliff = 490 m).
Because the projectile is thrown horizontally, we can determine that its initial vertical velocity (vy) is 0 m/s. Since there is no initial upward or downward motion, the initial velocity’s vertical component is zero.
There is a 490-meter vertical drop from the cliff’s height.
time (t):
(1/2) x 9.8 x t2 = 490
Both sides should be divided by (1/2) x 9.8.
490 / (1/2) x 9.8 is t2.
t2 = 100
Take both sides’ square roots:
t = -100
t = 10 s
We’ll apply the following equation:
h = (1/2)gt2
where g is the acceleration caused by gravity (about 9.8 m/s² on the surface of the Earth), t is the time it took to reach the ground, and h is the vertical distance fallen (in this case, the height of the cliff = 490 m).
Because the projectile is thrown horizontally, we can determine that its initial vertical velocity (vy) is 0 m/s. Since there is no initial upward or downward motion, the initial velocity’s vertical component is zero.
There is a 490-meter vertical drop from the cliff’s height.
time (t):
(1/2) x 9.8 x t2 = 490
Both sides should be divided by (1/2) x 9.8.
490 / (1/2) x 9.8 is t2.
t2 = 100
Take both sides’ square roots:
t = -100
t = 10 s