Generate Quiz 68AFCBED82164

Corrosion is the undesirable and desired reaction that results from the metal’s oxidation when it is exposed to the air.

The simplest, most simplified ratio of the various atom types in a chemical compound is expressed by the empirical formula. The ratios are always in the smallest whole numbers and give information about the relative numbers of each type of atom present.

The orbitals get larger as the energy levels rise. Thus, 4s>3s>2s>1s is the increasing order of the hybrid orbital’s size.

CH3-CH2-OH is an alcohol because it is an organic compound with at least one hydroxyl functional group (-OH) attached to a saturated carbon atom.

B) Cr(H2O)5Cl]Cl2.2H2O is the response.

Six ligands, six water molecules, and one chloride ion make up the complex. AgNO3 treatment of the complex causes the chloride ions to react with the Ag+ ions, forming the precipitate AgCl. With a mass of 28.7 g, the precipitate is equal to 0.2 moles of AgCl. There must be 0.2 moles of chloride ions in the complex because there is one mole of chloride ion in every mole of AgCl. This indicates that the complex contains two chloride ions that are coordinated to the central Cr atom. Water molecules make up the other four ligands.

Therefore, the formula of the complex is Cr(H2O)5Cl]Cl2.2H2O.

Because the other choices lack the proper quantity of chloride ions, they are incorrect. Three chloride ions are present in option A, four in option C, and six in option D.

Since combustion is an oxidation process that generates heat, it is invariably exothermic. The enthalpy change (ΔH) value is always negative since these processes are exothermic.

Esters are used as artificial flavors and fragrances because they are colorless chemical compounds with a sweet, fruity scent. They are derived from carboxylic acids and have the general formula RCOOR.

Let M1 and M2 be the masses of SO2 and He, respectively.
√M1/M2 = √64/4 = √16 = 4

Because of its shape, a p-orbital is concentrated in two lobes that face differently from one another. P-orbitals have a strong directional character as a result.

A crucial aspect of explaining molecular geometry and comprehending how atoms combine to form molecules is the directional nature of p orbitals. It influences covalent compounds’ forms, characteristics, and chemical reactivity.

Alkene undergoes hydrogenation during the Sabatier-Sendern reaction, breaking the double bond and creating a single bond. The net released energy is 30 kcal/mole (i.e., in one step, in the formation of alkene from alkyne) since the energy released in the formation of two sigma bonds is 174 kcal. This is known as the exothermic reaction, or heat of hydrogenation.

The following equation illustrates how the first rule of thermodynamics states that heat or work is the only way to modify internal energy or transfer energy.

The energy E=hc/λ of the mode times the density of states for photons and the probability that the mode is occupied is the energy density of a black body between λ and λ + dλ. This is the well-known formula for a black body’s energy density developed by Planck.

Both the E2 (bimolecular elimination) and SN2 (bimolecular substitution) reactions only require one step. In the E2 reaction, two molecules are extracted from the compound in a single step, whereas in the SN2 reaction, a bond is broken and another is formed simultaneously.

The hydrogen isotope tritium has a mass of three and a proton of one. Neutrons are mass number-number protons, and the result is 2. Thus, we can state that there are twice as many neutrons as protons.

The sodium metal response is the right one.Molten sodium chloride (NaCl) is electrolyzed in the Downs cell, an electrolytic cell that is frequently used to produce sodium metal.

The ideal gas law

PV = nRT

PV = W/M RT

When we rearrange the terms, we obtain

M = WRT/PV

where

M is the gas’s molar mass.

W = Gas Mass

R is the gas constant.

T is the gas’s temperature.

P is the gas pressure.

V = Gas Volume

We now obtain the value of the gas’s molar mass by entering all of the provided values into the formula above.

M= 1.25 ×62.36 × 301 / 715 × 0.25

M= 131.269 g/mol