C: 12.01 g/mol x 6 atoms = 72.06 g/mol
H: 1.01 g/mol x 12 atoms = 12.12 g/mol
O: 16.00 g/mol x 6 atoms = 96.00 g/mol
72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol is the total molar mass of glucose.
The next step is to determine the mass of carbon in 1.5 grams of glucose.
(Mass of glucose / Molar mass of glucose) x Molar mass of carbon is the mass of carbon.
(1.5 g / 180.18 g/mol) x 72.06 g/mol is the mass of carbon.
Carbon mass = 0.599 g
(Mass of carbon / Mass of sample) x 100 is the mass percent of carbon.
Carbon mass percentage is equal to (0.599 g / 1.5 g) x 100.
Carbon mass percentage = 39.93%
As a result, a 1.5 g sample of glucose contains about 39.93% mass percent carbon.
C: 12.01 g/mol x 6 atoms = 72.06 g/mol
H: 1.01 g/mol x 12 atoms = 12.12 g/mol
O: 16.00 g/mol x 6 atoms = 96.00 g/mol
72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol is the total molar mass of glucose.
The next step is to determine the mass of carbon in 1.5 grams of glucose.
(Mass of glucose / Molar mass of glucose) x Molar mass of carbon is the mass of carbon.
(1.5 g / 180.18 g/mol) x 72.06 g/mol is the mass of carbon.
Carbon mass = 0.599 g
(Mass of carbon / Mass of sample) x 100 is the mass percent of carbon.
Carbon mass percentage is equal to (0.599 g / 1.5 g) x 100.
Carbon mass percentage = 39.93%
As a result, a 1.5 g sample of glucose contains about 39.93% mass percent carbon.