Generate Quiz 68E96077556FF

Current is the net charge flow through a conductor in a unit of time. Amperes are used to measure current.

K is dependent upon

•System of units

• The medium’s separating charges’ nature

The torque will cause the rod PQ to rotate clockwise if the specified arrangement is in a horizontal plane.

The screen displays the direction of the magnetic field caused by current i0 at point P according to the right-hand grip rule. The current flowing through rod PQ is directed from P to Q. According to Fleming’s left-hand rule, the force at point P is therefore closer to the top of the screen. The rod rotates in a clockwise direction because it is pivoting.

The product of the vector area element and magnetic induction is known as magnetic flux.

Flux = B.ΔA

Flux = BΔAcosθ

Since cosθ reaches its maximum value (=1) at cos(0), the answer is 0 degrees. as well as 180

E’s formula:

E = q / 4πɛr2

Given that

E1 and E2 are equal.

q2 / 4πɛr22 = q1 / 4πɛr12

q2 / 4πɛ (2 r1)2 (r2 = 2r1) = q1 / 4πɛr12

q1 / 4πɛr12 = q2 / 16 πɛ r12

q1 / 4 = q2 / 16

q2 = 4q1

Therefore, choice A is the right one.

The total magnetic field that flows through a specific area is measured as magnetic flux. It is a helpful tool for explaining how the magnetic force affects an object occupying a specific space.

The result of connecting these three capacitors in series is one microcoulomb.

1/1 + 1/C2 + 1/C3

= ⅓ + ⅓ + ⅓

= (1+1+1) / 3.

= 3 / 3.

1/C = 1.

C = 1

The answer is C because soft iron cores are used in transformers because they minimize energy loss and have high magnetic permeability, which permits magnetic flux coupling between primary and secondary coils.

This is a typical response. Volts is EMF’s SI unit. The SI unit for potential difference is also volts. 1 Volt is equal to Joule/Coulomb

Its winding is two-phase.

There is no computation needed to answer this question.

Just be aware that there won’t be an attractive or repulsive force between them if we add -5C to both. This will cause the +5C point charge to become 0C, or without any charge.

Q is equal to 7.2x105C.

C = 6×10-6F

Since Q=CV

V = Q/C

V= 7.2x105C / 6×10-6F

V = 1.2x1011V

The SI unit of capacitance is a farad. It is the quantity of electric charge that a capacitor can hold per unit of voltage. For every volt of potential difference, one farad is equivalent to one coulomb of electric charge. Coulomb/volt, then.

The charge-mass ratio of a proton is 1 C/amu. We can state that the charge-mass ratio is inversely proportional to the radius of deflection. Because of this, a proton is more deflected than an alpha particle because it has a smaller radius of deflection, which causes it to turn sharply.

The propensity of a coil to resist changes in current within itself is known as self-inductance. An EMF is produced whenever a coil’s current changes, and it is proportional to the rate at which the current changes.

The magnetic field density (B) can be found using the following formula:

B=F/IL {where I is the current, L is the conductor length, and F is the force}

Replace the SI units in the formula:

B = N/Am

Consequently, the magnetic flux is BA:

B = N/Am x m2

= NmA-1

A current-carrying conductor experiences force equal to BIL.

The equation F = qVBsinθ, where q is the charge, B is the magnetic field, V is the charge’s velocity, and θ is the angle between the velocity vector and the magnetic field vector, provides the force acting on a charge traveling through a magnetic field.

The angle between the velocity vector and the magnetic field vector in this instance is 0° since the electron is traveling along the line of force in magnetic field B. Sinθ = sin(0°) = 0 implies this.

When we enter sinθ = 0 into the formula F = qVBsinθ, we obtain:

F = qVB(0) = 0.

This indicates that there is no force acting on the electron, so choice D is the right one.

A force is applied to a charge as it passes through a magnetic field, and this force is determined by:

F = QvB sinθ

The motional electromagnetic field (EMF) created when a conductor passes through a static magnetic field is known as QvBl.

The definition of electric potential, which is work done per unit charge in moving that charge from one location in the electric field to another, is merely being revised in this question.

The definition of electric potential excludes all other possibilities.

When a current-carrying conductor is moved in an external magnetic field, motional electromagnetic fields are created. If the conductor is moved quickly, the motional emf will be higher. The induced emf is equal to the change in magnetic flux per unit of time. As a result, shifting magnetic fields over time will be the best choice.

The rate at which flux changes per unit of time is known as the induced Emf.

emf is equal to ∆Ø/∆t.

When the amount of flux flowing through the coil in a given amount of time doubles,

E’ = 2(∆Ø/∆t).

E’ = 2E.

The emf doubles if the flux is “doubled” because E is directly proportional to the flux change.

I= 2.75A , L= 60cm , B= 9
F=ILB provides the force acting on a current-carrying conductor.

F = (2.75)(0.6)(9) 60 cm = 0.6 m
F is 14.85.

Because accelerating charges result in shifting magnetic and electric fields, this choice is accurate. Magnetic fields are created when electric fields change, and electric fields are created when magnetic fields change. Electromagnetic waves propagate as a result of this interaction between the induced electric and magnetic fields.

The voltage is stepped up and down using a transformer.The transformer’s power doesn’t change.

Stepping up the voltage before transmission and stepping it down at the far end once the current has reached its destination are two ways to reduce currents during efficient transmission.

Transformers are used to step up and down the voltage for AC power transmission.

The turns ratio, which is the ratio of the secondary coil’s (Ns) to primary coil’s (Np) turns, is a term used in transformers. The turns ratio in this instance is 10, indicating that the secondary coil’s number of turns is ten times that of the primary coil.
Because it dictates how a transformer transforms voltage, this relationship is significant. The turns ratio indicates that the secondary coil’s voltage (Vs) is proportional to the primary coil’s voltage (Vp) by the same amount. The secondary voltage is therefore ten times the primary voltage if the turns ratio is 10: Vs = 10Vp.

According to the definition, motional E.M.F. occurs when a conductor of length L moves across magnetic field B, causing a potential to appear across its end.

In each of these, non-inductive resistances are employed.

Resistance boxes, voltmeters, and ammeters can all make inaccurate readings due to inductive resistances. The reason for this is that inductive resistances produce a magnetic field that opposes the current change. This may result in an erroneous measurement or the pointer deflecting in the wrong direction.

Since non-inductive resistances don’t produce a magnetic field, they don’t skew the measurements that these instruments take. For this reason, they usually use non-inductive resistances.

Using non-inductive resistances has the following benefits:

They offer precise measurements.
External magnetic fields have less of an effect on them.
Over time, they become more stable.

The current carrying loop functions similarly to a dipole with two poles, one at the north and one at the south.

A current transformer’s secondary turns are always kept closed, creating a closed loop that permits the secondary current to continuously pass through the protection or measurement devices. Because they either don’t require current measurements or don’t have a specific requirement to keep the secondary turns closed, the other options are incorrect.

The induced EMF would likewise be “zero” when the current was “zero.” Furthermore, since EMF is the rate at which flux changes, naturally, magnetic flux would likewise be “zero” if the EMF was.

Cathode Ray Oscilloscopes (CROs) use the oscillation principle to create and show electrical waveforms on a screen. It is not, however, a CRO working principle.A Cathode Ray Oscilloscope (CRO) uses an electron beam to show electrical waveforms on a screen as part of its operation. Therefore, none of these is the right choice.

Faraday’s law said that “The average EMF induced in a conducting coil of N loops is equal to the negative of the rate at which the magnetic flux through the coil is changing with time.”

Y should be connected to the voltage, and the time base should be turned on.

When a machine’s parts rotate, friction losses occur.

There is no frictional loss in a transformer regardless of the loading condition because it is a static device, meaning it has no moving parts of any kind.

Therefore, choice D is the right one.

This choice is accurate since both electric and magnetic fields can be created by a fluctuating current. Because current charges move in a unit of time, an electrical field and a magnetic field are created around the charges as a result of their motion.

The area of the plates, the separation between the plates, and the presence of a dielectric between the plates all affect how much energy a parallel plate capacitor can store. By increasing the Aaea of the plates, reducing the distance between them, and putting a dielectric between them, the amount of energy stored will rise.

To determine the transformer’s core loss, an open-circuit test is conducted. The transformer’s primary winding is the subject of this test.

The capacitance of the capacitor stays constant when the charge applied to it doubles.The capacitance is solely determined by the conductors’ geometrical arrangement.

The area of the plates, the separation between the plates, and the dielectric’s capacity to withstand electrostatic forces all have an impact on a capacitor’s capacitance.

Since dot products are being used, the magnetic flux is a scalar quantity. Note: The magnetic flux is zero when the magnetic field is parallel to the closed surface. The reason for this is that the area vector and the magnetic field vector are at a 90° angle.

The distance between the plates has an inverse relationship with the capacitance. The capacitance would double with a halving of the distance, giving us 2C.

Transformers require AC voltage to function.

All current sources transform non-electrical energy, including heat, mechanical, chemical, and solar energy, into electrical energy. Current comes from a wide variety of sources.

The magnetic field 8m below can be calculated using the following formula because the magnetic field lines are dispersed in circular rings:

B = μo I / 2𝜋R

where the magnetic field is denoted by B. R is the distance at which the magnetic field needs to be calculated, and I is the current. μo has a value of 4𝜋 x 10-7 H/m.

Our solution is obtained by substituting these values in the equation above:

B = 4𝜋 x 10-7 x 100 / 2𝜋 x 8

The external effort required to move a charge from one place in an electric field to another is called the electric potential difference, or voltage.

Δ [ V] = [U] / q

Therefore, choice B is the right one.

The product of the area and the magnetic field component perpendicular to the loop’s plane yields the maximum flux through a loop with area A in a magnetic field B. In this instance, the loop is positioned perpendicular to the x-axis in the y-z plane. Consequently, the x-component of the magnetic field, which is 2 Tesla, provides the component of the magnetic field perpendicular to the loop’s plane.

Therefore, the product of the loop’s area and the magnetic field’s x-component yields the maximum flux through the loop, which is:

The maximum flux (Φ) is equal to B×A = 2× 10 = 20 Weber, where Φ = BAcosθ Cos (0°) = 1.

E=velocity x rod length x magnetic field intensity is the formula for emf.

Since the rod is only 25 cm long, it must first be converted to meters. = 25×10-2

E= 0.5 x 0.25 x25 x10-2 = 3.13 x 10-2V

The amount of magnetic field that flows through a specific area is known as the magnetic flux. It can be found as the dot product of area A and magnetic field B. An area vector’s direction is normal, or perpendicular, to the area’s surface.

Inside a solenoid, B=μ0IN/L

where the current is I,

The number of turns is N.

L stands for length.

Consequently, each of these variables affects the magnetic field inside a solenoid.

When the electric field is uniform, the two electric field lines are

1. straight

2. in parallel

3. equally spaced

A field where the field strength stays constant is called a uniform electric field.

Kinetic or mechanical energy can be transformed into electrical energy by a generator. It has the ability to generate both AC and DC current. An alternating current that alternates between directions is produced by an AC generator. However, a direct current only flows in one direction in a DC generator.

The angle between the wire L and the magnetic field B is denoted by θ in F = ILB sin θ. When the angle is 90° and they are perpendicular to one another, the force F is:

F is equal to ILB sin 90.

F = ILB (1)

F = ILB

Therefore, when the conductor is positioned perpendicular to the magnetic field, the force is at its highest. The force is zero when they are parallel:

F = ILB sin 0

F = ILB (0)

F is equal to zero.

The number of turns in a coil directly correlates with the magnetic flux associated with it. Each turn of a coil adds to the magnetic flux when it has several turns. A coil’s connection to magnetic flux increases with its number of turns.

A positive charge feels a force when it is exposed to an electric field. A positive charge experiences a force that is parallel to the lines of the electric field and points in the same direction as the field. Given that positive charges are repelled from areas of lower electric potential and attracted to areas of higher electric potential, this makes sense. The positive charge feels a force in the direction of the electric field since the electric field points in the direction of decreasing potential.

Given that magnetic flux is the scalar product (dot product) of the magnetic field, option B is accurate. vector as well as an area vector. It is a dot product since the area and magnetic field are parallel to one another. Simply put, magnetic flux is the flow of hypothetical magnetic field lines through a given area without requiring a specific direction.

The direction of the magnetic lines of force is such that they start at the north pole and end at the south pole. This is due to the fact that a magnet’s north pole is marked by outward-pointing magnetic field lines, while its south pole is marked by inward-pointing magnetic field lines.

Since the magnetic lines of force are constant, the magnet must be traversed. They create loops that encircle the magnet rather than traveling through it in a straight line.

Neither of the poles causes the magnetic lines of force to disappear. Outside the magnet, the magnetic field would be zero if they did.

Since the element number of selenium (Se) is 34, its two and a half spins are empty. Thus, it primarily functions as photocells, which use solar energy as a charge source. It goes without saying that it functions as an insulator in the dark and as a conductor in the light.

The magnetic flux through the ring changes as the magnet gets closer, and Lenz’s law states that current is induced in the ring, creating its own magnetic field that counteracts the change in flux. Consequently, the ring’s induced magnetic field will be in opposition to the magnet’s field because, in accordance with Lenz’s law, it opposes the change that initially caused it. As seen below, the ring moves away from the approaching field as a result of the repulsion.

Faraday’s Law: According to this law, when the magnetic flux through a closed wire loop changes over time, an electromotive force (emf) is induced. This law is represented by the equation “emf = -N(ΔΦ/Δt)” in which “emf” is the induced electromotive force, “N” is the number of loop turns, and “ΔΦ/Δt” is the rate at which magnetic flux changes.
As a result of Faraday’s Law, Lenz’s Law establishes the direction of the induced current in the loop. It claims that the induced current is oriented in a way that is opposite to the change in magnetic flux that generated it.

F = BIL sin (θ)

Taking the units into account:

Tesla = (Newton)/(Ampere x metre)

The ratio of the permeability of the medium (μm) to the permeability of the vacuum (μ) is known as the relative permeability, or μr.
The formula is as follows: μr = μ/μm

It has no unit since it is a ratio of two comparable quantities.

The law of electromagnetic induction was first presented by Michael Faraday. According to Faraday’s law of electromagnetic induction, a conductor in a fluctuating magnetic field will induce a current. Any slight change in the coil’s magnetic field will cause an induced electromagnetic field (emf) in line with Faraday’s first law.

Both an electric field and a magnetic field are present in a moving charge. Because of the charge itself, there is an electric field. The motion of the charge creates the magnetic field.

The capacitance of a capacitor is increased when a dielectric material is placed between its plates. The material’s relative permittivity or dielectric constant (k) controls how much of this increase occurs. The capacitance of the capacitor with the dielectric material divided by the capacitance of the same capacitor without the dielectric material is known as the dielectric constant. In mathematics, C’=k×C, where C is the capacitance without the dielectric, is the capacitance with the dielectric (C’). According to this formula, the presence of a dielectric material causes the capacitance to increase by a factor of k. As a result, option A) Increases by k correctly depicts how a dielectric affects capacitance.

Given:

Charge(q)=2e-

3.0V is the potential difference (V).

Locate:

Energy =?

Answer:

Energy equals completed work.

Work = qV

Energy = 2e×3 = 6eV

Energy = 6×1.6×10-¹⁹

Energy=9.6×10-¹⁹J

The force acting on a wire positioned at right angles to the magnetic field per unit current per unit length is known as the magnetic flux density (B).

There are several names for magnetic field strength, including magnetic intensity, magnetic field intensity, and magnetic field strength.

By taking into account the individual electric fields generated by each charge and their vector sum, the net electric field directed to the left in the given configuration of charges X, Y, and Z can be found.

Let’s examine the circumstances:

Charge X: Its electric field points in all directions in the direction of the charge because it is negative (-).

Charge Z: Its electric field points in all directions away from the charge because it is positive (+).

Let’s now examine each position’s net electric field:

A. At location X:

Charges X and Z are the cause of the electric field at position X. Both add to the electric field that is coming from X. At X, the net electric field is pointing left.

The capacitance rises and the plate separation decreases when the key is pressed. Capacitance is independent of the external circuit and solely depends on the capacitor’s construction.

The speed of light is equal to the photon velocity. Although photons have no mass, their energy is E = hf = hc/λ. Planck’s constant is h = 6.626*10-34 Js in this case. The electromagnetic wave’s wavelength and photon energy are inversely correlated.

E=6.626×10−34 × 3×108​/1240×10-9 ≈ 1.00 eV.

At the Earth’s magnetic equator, the magnetic field is 30 microteslas strong. Near the poles, where the magnetic field lines converge, maps of the Earth’s surface magnetic fields reveal stronger fields that are about twice (60 microteslas) as strong as those at the equator. Compared to a tiny bar magnet that has about 10,000 microteslas, this is incredibly weak.

The following formula provides the capacitance of a parallel plate capacitor:

C = Aεo/d

where ε0 is the permittivity of free space, d is the distance between the plates, A is the area of each plate, and C is the capacitance.

Every other choice is wrong.

A machine that transforms mechanical energy into electrical energy is called an electric generator. It works on the basis of electromagnetic induction, which is the process by which a conductor moves through a magnetic field and induces a voltage in the conductor.

Magnetic flux density x current x sin(θ) = force/length

For maximum force, sin(θ) = 1.

The answer is provided by entering the values.

A is the right choice.

In line with Coulomb’s law:

F1 = k/d2.

K = F1 × d2

F2 = k /(d/2)2

F2 = 4F

There is only one right answer because this is a numerical question.

V = W/q

V = P.E./q