A circular loop of area 0.05 m2 rotates in a uniform magnetic field of 0.2 T. If the loop rotates about its diameter which is perpendicular to the magnetic field, find the flux linked with the loop when its plane is normal to the field.
Elimination Tool
The area vector with the field will be (90 – 90) = 0 since the plane is normal (90).
B (magnetic field) = 0.2 T
A (area) = 0.05 cm²
= 0
The formula Flux() predicts that
= B A cos
= 0.2 0.05 cos (0)
Keep in mind that cos (0) = 1.
= 0.01 Wb
The area vector with the field will be (90 – 90) = 0 since the plane is normal (90).
B (magnetic field) = 0.2 T
A (area) = 0.05 cm²
= 0
The formula Flux() predicts that
= B A cos
= 0.2 0.05 cos (0)
Keep in mind that cos (0) = 1.
= 0.01 Wb