I1=5.0A is the initial current.
I2=0A for the final current
Change in current, dl=I1−I2=5A
Time spent charging, t=0.1s
Average emf, e = 200V
The relationship for average emf for the coil’s self inductance (L) is as follows:
e=L x current change rate
L=e/rate of current change
L = 200/5/0.1
L = 4H
Thus, the coil’s self-inductance is 4H.
I1=5.0A is the initial current.
I2=0A for the final current
Change in current, dl=I1−I2=5A
Time spent charging, t=0.1s
Average emf, e = 200V
The relationship for average emf for the coil’s self inductance (L) is as follows:
e=L x current change rate
L=e/rate of current change
L = 200/5/0.1
L = 4H
Thus, the coil’s self-inductance is 4H.