5.3 x 10^-5 C = Q
V equals 6.0 V.
Applying Q = CV, we obtain:
C = Q/V = (5.3 x 10^-5 C)/(6.0 V) = 8.83 x 10^-6F
Let’s now determine how much charge the capacitor stores when it is connected to a 9.0 V battery. We possess:
V equals 9.0 V.
C = 8.83 x 10^-6 F
Applying Q = CV, we obtain:
Q = CV = (8.83 x 10^-6 F) x (9.0 V) = 7.95 x 10^-5 C
5.3 x 10^-5 C = Q
V equals 6.0 V.
Applying Q = CV, we obtain:
C = Q/V = (5.3 x 10^-5 C)/(6.0 V) = 8.83 x 10^-6F
Let’s now determine how much charge the capacitor stores when it is connected to a 9.0 V battery. We possess:
V equals 9.0 V.
C = 8.83 x 10^-6 F
Applying Q = CV, we obtain:
Q = CV = (8.83 x 10^-6 F) x (9.0 V) = 7.95 x 10^-5 C