The code contains two mistakes.
Justification:
The if statement in C uses assignment incorrectly. It expects a condition to evaluate to true or false. The provided code uses x = 1 as the condition. Nevertheless, the value assigned—in this case, 1—is returned by the assignment operator =. Since 1 is regarded as a truthy value in C, the if statement always evaluates to true.
This can be fixed by comparing the value of x with 1 using a comparison operator such as ==. The updated code is as follows:
C
void main() {
int x = 0;
If (x == 1) {
printf(“Hello”);
Otherwise, `
printf(“Bye\n”);
~
~
The semicolon that follows the printf statement in the if block is missing: The semicolon that follows the printf(“Hello”) statement in the if block is missing. This is a syntax error because statements in C must be terminated with semicolons.
The code contains two mistakes.
Justification:
The if statement in C uses assignment incorrectly. It expects a condition to evaluate to true or false. The provided code uses x = 1 as the condition. Nevertheless, the value assigned—in this case, 1—is returned by the assignment operator =. Since 1 is regarded as a truthy value in C, the if statement always evaluates to true.
This can be fixed by comparing the value of x with 1 using a comparison operator such as ==. The updated code is as follows:
C
void main() {
int x = 0;
If (x == 1) {
printf(“Hello”);
Otherwise, `
printf(“Bye\n”);
~
~
The semicolon that follows the printf statement in the if block is missing: The semicolon that follows the printf(“Hello”) statement in the if block is missing. This is a syntax error because statements in C must be terminated with semicolons.