If n (Ex. = 18 and n (E2. = 6
and n (5. = 36 also E₁ and E₂ are
independent then P(E1∩E2) = ?
THE RIGHT ANSWER (C)
When E1 and E2 are independent, we can use the following formula to determine where they intersect:
P(E1∩E2)=P(E1)×P(E2)
We can determine P(E1) and P(E2) given that n(E1)=18, n(E2)=6, and n(S)=36 (where S is the sample space):
P(E1)=n(S)n(E1)=18/36=1/2
P(E2)=n(S)n(E2)=6/36=1/6
We can now compute P(E1∩E2):
P(E1∩E2)=P(E1)×P(E2)=1/2×1/6x1/6=1/12
Thus, the right response is:
c) 1/12
THE RIGHT ANSWER (C)
When E1 and E2 are independent, we can use the following formula to determine where they intersect:
P(E1∩E2)=P(E1)×P(E2)
We can determine P(E1) and P(E2) given that n(E1)=18, n(E2)=6, and n(S)=36 (where S is the sample space):
P(E1)=n(S)n(E1)=18/36=1/2
P(E2)=n(S)n(E2)=6/36=1/6
We can now compute P(E1∩E2):
P(E1∩E2)=P(E1)×P(E2)=1/2×1/6x1/6=1/12
Thus, the right response is:
c) 1/12