Generate Quiz 69C702255FFA2

When the conductor’s length is cut in half, the resistance will also be cut in half; the two are directly proportional.

L/A = R

Water pipe leaks are found using radiation.

To find water leaks, two primary forms of radiation are employed:

A chemical that is injected into the water supply is known as a radioactive tracer. A radiation detector is then used to track the tracer. The tracer will be found at the leak’s location if one exists.
Sound waves: By listening for the sound of water escaping, sound waves can be used to find water leaks. Although this approach is less costly and applicable in locations where radioactive tracers are prohibited, it is not as accurate as radioactive tracers.

The double of the peak voltage is the peak to peak voltage.

Adjacent nodes, or points with zero amplitude, are separated by half the wavelength (λ/2) of a stationary wave.

When two waves of the same amplitude and frequency move in opposite directions, they superimpose to form a stationary wave. Nodes are the locations where the wave’s amplitude is zero, and antinodes are the locations where it is at its maximum.

The distance between neighboring nodes in a stationary wave can be computed as follows:

distance between adjacent nodes = λ/2

where λ is the wave’s wavelength. Consequently, the wave’s wavelength determines the separation between neighboring nodes.

When it comes to the heat engine, the claim that “Efficiency of the Carnot engine working between two same temperature, depending on the nature of the working substance” is untrue.

When the star’s wavelength was measured, it was found to be similar to that of sodium, which has a wavelength of 589 nm. The wavelength of the sodium line, which was observed in the laboratory, was determined to be 497 nm. This indicates that as the star moves away, the wavelength increases.

Q = mL, where L is the specific latent heat of fusion of ice, m is the mass of ice, and Q is the quantity of thermal energy needed to melt the ice.
When we change the specified values, we obtain:

1.002 x 106 J = m x 334 J/g
Solving for m, we get: m = (1.002 x 106 J) / (334 J/g) = 2997.60 g m= 3000 g = 3 kg

The other choices are wrong mathematically.