Generate Quiz 6A0742BC44E5B

Reason: It has a methyl group on the third carbon and a chlorine group on the second. Five carbons make up the longest chain.

Here, Cl2 breaks down into free radicals when exposed to UV light, replacing one of the hydrogen atoms in isobutane. This is an example of free radical substitution.

Fluorobutane is yellow.

Chlorobutane= white

Bromobutane has no color.

Iodobutane= pink

Because of their highly polarized bonds and the significant difference in electronegativities between the halogen and carbon atoms, alkyl halides are extremely reactive. The order is [ >Br> CI>F] according to the leaving ability. The carbon-halogen bond’s strength and length are more important than its polarity, which would produce the opposite order.

The C-Br bond breaks in step 1 of the SN1 reaction mechanism, and Br leaves with the bonding electron pair to form the bromide anion Br– and tertiary carbocation. This step is the slowest in the entire mechanism and only entails a highly endothermic bond-breaking process.

The symbol for the methyl group is ‘-CH3’. Four methyl groups—(CH3)4 and a lead group—are highlighted in the compound’s name as provided in the question. Option B is the right response since we can deduce that the lead is the compound’s central atom.

The Friedel-Craft reaction is catalyzed by anhydrous aluminum chloride.

Polar aprotic solvents favor the SN2 reaction. While SN1 reactions are relatively slow in aprotic solvents, SN2 reactions proceed more quickly.

Since they lack hydrogen atoms bound to other electronegative atoms like O, N, and F, polar aprotic solvents are incapable of forming hydrogen bonds. Their protons are not acidic. Acetone, ethers, and chloroform are a few examples of polar aprotic solvents. Carbon tetrachloride (CCl4) is an aprotic solvent that contains non-polar covalent bonds between carbon and chlorine.
Therefore, choice C is the right one.

Of all the halogens, fluorine has the highest electronegativity and the smallest atomic radius, which results in the highest bond energy. This indicates that fluorine can bind to carbon atoms in a very strong way that takes a lot of energy to break.

Since M-toluidine is the main product of the reaction between p-chlorotoluene and KNH2 in liquid NH3, it is the right choice.