Generate Quiz 6A2CD94387BAF

In free space, the permittivity is roughly 8.85 x 10-12 C2 /(N.m2). Option A is correct because this is a fact.

One electron, which is equivalent to the charge of one proton, is the smallest indivisible unit of charge. Thus, choice C.
An electron has a minimum charge of 1.6 x 10-19 C.

The electric field of a capacitor has the capacity to store energy.

An electric field forms between the plates of a capacitor when it is charged, accumulating electric potential energy. Because the positive and negative charges on the capacitor plates are separated, the energy is stored in the electric field. When the capacitor discharges, the energy is released, and charges move from one plate to the other, creating an electric current flow.

The capacitance of the capacitor stays constant when the charge applied to it doubles.The capacitance is solely determined by the conductors’ geometrical arrangement.

The area of the plates, the separation between the plates, and the dielectric’s capacity to withstand electrostatic forces all have an impact on a capacitor’s capacitance.

Because C is inversely proportional to distance, capacitance will increase three times for every three decreases in distance.

V = W/q

V = P.E./q

The charge stays the same in series. Options C and D are thus nullified.

In order to determine total capacitance:

1/C = 1/12 + 1/24

C = 8F

C = Q/V

8 x 36 = 288C

Thus, option A is the right response.

The stored energy is equal to Q²/2C, where Q is the charge and C is the constant capacitance.

Consequently, the square of charge and energy are directly proportional. Thus, energy increases four times when charge increases two times.

E’s formula:

E = q / 4πɛr2

Given that

E1 and E2 are equal.

q2 / 4πɛr22 = q1 / 4πɛr12

q2 / 4πɛ (2 r1)2 (r2 = 2r1) = q1 / 4πɛr12

q1 / 4πɛr12 = q2 / 16 πɛ r12

q1 / 4 = q2 / 16

q2 = 4q1

Therefore, choice A is the right one.

Positive charges are repelled by one another, so the electric field surrounding a single positive charge is ‘radially outward’. Electric fields are shown as beginning on positive charges and ending on negative charges when they are represented by lines of force, also known as field lines.

W = ΔK.E
K.Ei = 0 and W = K.Ef – K.Ei
W = K.Ef

Since V=W/q W=qv K.E=qv, as we know, D is the right choice.

One coulomb of charge contains 6.25×1018 electrons.

An object’s ability to exhibit electrostatic attraction or repulsion with other charged objects is known as its charge. While positive and negative charges attract one another, two positive or negative charges will repel one another.

According to Coulomb’s Law, the electrical force between two charged objects is inversely proportional to the square of their distance from one another and directly proportional to the product of the charges on the objects. Therefore, Option D is the right response to this query.

Volts per meter (V/m) is the unit of measurement for electric field strengths (E).

Electric field lines are always directed toward a negative point and away from a positive charge. A positive charge is where electric fields begin, and a negative charge is where they end. This demonstrates that choices B and D are not appropriate.

Since electrons are negatively charged particles that move from the lower potential terminal to the higher potential terminal, they flow in the opposite direction of the electric field—from the negative to the positive poles. Option C is therefore accurate.

A is the right choice.

E = ½ Q V is the amount of energy stored in the capacitor.

= ½ × 27 × 10-6 × 18

= 2.43×10-4 J

There can only be one response because this is a numerical question.

The relationship between voltage and capacitance is inverse.

Using the formula:

Q = CV.

Shortcut: The total voltage from the battery is equal to the sum of the two voltages in the series circuit. Therefore, the answer will be the option where the sums equal 120.

The following formula provides the energy gained by a particle with charge q when it accelerates through a potential difference V:

U = qV

Option D is the right choice because it displays this.

A scalar quantity is electric potential. The electric potentials of the two positively charged point charges will be added at their midpoint, doubling the potential.

The answer

One meter, one meter

V=?———-+q——–V=?

V = k q/r + k q/r

V = k q/r + k q/r

V = 2 k q/r.

Option A: The combination of several capacitors connected in parallel is represented by the formula C = C + C + C +… + C.

Therefore, A) Parallel is the right response.

The capacitors are connected in parallel, with the positive and negative terminals of each capacitor connected to each other. Each capacitor experiences the same potential difference as a result. The sum of the individual capacitances is the combination’s total capacitance.

The given expression indicates a parallel combination because all of the capacitors are added together.

Where K is the Coulomb’s constant, V=KQ/r

V=(9*109)*(2*10-6)/1 = 18000 volts = 1.8*104

Electrostatics is the study of how charges behave when they are at rest.

The capacitance rises and the plate separation decreases when the key is pressed. Capacitance is independent of the external circuit and solely depends on the capacitor’s construction.

Projecting a charged particle perpendicular to a magnetic field causes

In a plane perpendicular to the magnetic field plane, the particle’s path is circular.

A is the right choice.

An apparatus that stores electric charges in an electric field is called a capacitor. An electrical component that stores potential energy is called a capacitor. Positive and negative energy are stored in capacitors on two distinct plates that are isolated from one another by an insulator. The abbreviation for a capacitor or capacitors is cap(s).

First, F=4πϵ0​1​r2q1​q2 is the force between charges, say q1 and q2, separated with distance r.Step 2: Calculate the new force

When both the charge and the distance between charges double, for example, q1′ = 2q1, q2′ = 2q2, and r′ = 2r
This will be the new force:
F′=4πϵ0​1​r′2q1′​q2′​​F′=4πϵ0​1​(2r)2(2q1​)(2q2​)​=4πϵ0​1​r2q1q2 = F
As a result, the force will not change.

Every distance: Coulomb’s law has been experimentally confirmed for distances ranging from galaxies to atomic nuclei. As a result, Coulomb’s law is widely accepted to be a universal law that holds true for all distances.

One name for the force per unit charge is:

F/q = E. This formula relates to the intensity of an electric field.

An object’s electric charge—whether positive or negative—determines how it will react to an electric or magnetic field. Coulombs, or Cs, are the SI unit of charge.

According to Coulomb’s law, electric force is inversely proportional to the square of separation and directly proportional to the product of two point charges. Note that we add a constant to the equation after removing the sign of proportionality, making it become

Force = Kq1q2 / r2

As stated on page 40 of the Physics Sindh Textbook.

The statement “….. two static point charges…..” makes it very evident that the charge is at a single location in space.

When an electron is released from an electric field, it accelerates in the opposite direction of the magnetic field.

Q is equal to 7.2x105C.

C = 6×10-6F

Since Q=CV

V = Q/C

V= 7.2x105C / 6×10-6F

V = 1.2x1011V

Voltage or potential difference is the amount of work done per unit of charge.

The electric potential difference is the difference in the electric potential energy of a unit charge between two points in the electric field.

According to Coulomb’s law, the force of attraction or repulsion between two electric charges acting in a straight line is inversely proportional to the square of their distance from one another and directly proportional to the product of their charges.

1/C=1/C1+1/C2

1/C = ½ + ¼

1/C = ¾

C is equal to 4/3.

Therefore, 4/3 μF is the effective capacitance.

The distance between the plates has an inverse relationship with the capacitance. The capacitance would double with a halving of the distance, giving us 2C.

A is the right choice.

In line with Coulomb’s law:

F1 = k/d2.

K = F1 × d2

F2 = k /(d/2)2

F2 = 4F

There is only one right answer because this is a numerical question.

V/d = E

Note that the distance should be measured in meters. Thus, 2 cm = 0.02 m.

20-(-20)/0.02

= 2000 V/m

q = 3e

q = 3 (1.6 x 10-19)

V is equal to 2V.

E equals qV.

E = (3 х 1.6 x 10-19)(2V)

E = 9.6 x 10-19 J

Option B is the right choice because this is a numerical question with only one possible response.

The dielectric that is positioned between the capacitor’s plates weakens the electric field between them, which causes a slight voltage to exist between them for the same charge. For a lower voltage, the capacitor can hold more charge. As a result, the capacitance rises.

The total capacitance of capacitors connected in parallel is determined using

Ct = C1 + C2 + C3

Ct = 6μC

Among the provided, this yields the highest net capacitance.

The following formula provides the capacitance of a parallel plate capacitor:

C = Aεo/d

where ε0 is the permittivity of free space, d is the distance between the plates, A is the area of each plate, and C is the capacitance.

Every other choice is wrong.

Using the following formula, we can easily determine how many electrons must be removed from a body in order to produce one coulomb of charge:
‘Q’ stands for the charge, ‘n’ for the number of electrons, and ‘e’ for the electronic charge in the formula Q = ne (*).

1.6 * 10⁻¹⁹ C = 1 Coulomb e = Charge ‘Q’
Then, using (*), we get 1 = n * 1.6 * 10⁻¹⁹ 1/1.6 * 10⁻¹⁹ = n 6.25 * 10¹⁸ = number oof electrons
Therefore, 6.25 * 10¹⁸ electrons must be removed from a body in order to generate one coulomb of charge.

This question is a high-yield concept because it has been asked repeatedly in other papers.

With the Greek words xeros meaning “dry” and graphos meaning “writing,” the word “xerography” refers to an electrostatic process used in the production of copy machines.

The electrostatic potential varies as we move from the positive charge toward the negative one; at any given point, the electric field is negative of the potential gradient. A declining potential is indicated by a negative sign.

Coulomb’s Law is defined as follows: the electrostatic force (F) between two point charges is inversely proportional to the square of their distance (r2) and directly proportional to the product of their charge magnitudes (qq). In terms of mathematics:

F = kqq/r2

where k is the proportionality constant.

Option E is therefore the right one.

E = v x B
E=12×8.75 E=105units

The distribution of charges between two objects becomes less uniform when there is frictional force between them; that is, the net charge on the objects’ surfaces changes from positive to negative, producing an electric field. Consider it frictional induction. Additionally, remember that only negative charges are transferred; charges cannot be created because they are already present in an object.

The equivalent capacitance is lowest when n capacitors are connected in series.

Cseries = C/n

and the equivalent capacitance reaches its maximum when n capacitors are connected in parallel.

Cparallel = nC

Using their ratios,

The following formula provides the energy stored in a capacitor:

1/2 × C × V2 = E

where V stands for voltage, C for capacitance, and E for stored energy.

Since V = 10 V and C = 2 uF in this instance,

E = 1/2 × 2 uF × (10 V)2 = 100 uJ

The following formula provides the charge on each capacitor plate:

Q = C × V

Since V = 10 V and C = 2 uF in this instance,

Q = 2 uF × 10 V = 20 uC

Consequently, D) Q = 20 uC and E = 100 uJ is the right response.

Gaussian surface: In three dimensions, the Gaussian surface is a closed surface that is used to compute a vector field’s flux. The gravitational field, electric field, or magnetic field are examples of these vector fields.

The electric field should be directed toward Q as it shifts away from positive charges and toward negative charges. Since electric potential is a scalar quantity, directions should not be taken into account when adding it. The potential at point X will be zero since the charges are opposite and equal at the same distance from it.

C = ε0A/d

when there is free space or air between the plates. The permittivity of free space is denoted by ε0.

In a uniform or non-uniform electric field, an electric dipole always experiences a torque. However, a dipole will also feel a net force of attraction in an uneven electric field. Thus, in a non-uniform electric field, the electric dipole experiences both force and torque.

Charge development is the outcome of electrons moving from one body to another. Thus, the number of electrons that one body contributes equals the number of electrons that the other body receives.

∴ While the overall mass of the system stays constant, the mass of the negatively charged body slightly increases and the mass of the positively charged body slightly decreases.

Therefore, (D) is accurate.

The result of connecting these three capacitors in series is one microcoulomb.

1/1 + 1/C2 + 1/C3

= ⅓ + ⅓ + ⅓

= (1+1+1) / 3.

= 3 / 3.

1/C = 1.

C = 1

The definition of electric potential, which is work done per unit charge in moving that charge from one location in the electric field to another, is merely being revised in this question.

The definition of electric potential excludes all other possibilities.

A or B are the only options with the same charge throughout the circuit, so either of these answers is correct.

Q = CV

Series capacitance can be computed as follows:

1/C = 1/C1 + 1/C2

1/C = 1/12 + 1/24

1/C = 2+1/24

1/C = ⅛

C is equal to eight microfarads.

->Q=CV

Q = (8×10^-6)(360)

Q = 2880 x 10-6 C

The formula for the electrostatic force is F = kq1q2/r². Therefore, the square of the distance between the two charges and the force between them are inversely proportional. Therefore, the force becomes 1/9 times if the distance increases by 3.

Option B is therefore accurate.

(kq1q2/r2) /(kq1 q2/(3r)2) = F1 / F2

F1/9 = F2

The coulomb, denoted by the letter “C,” is the SI unit of electric charge. The quantity of charge that flows through an electrical conductor carrying one ampere per second is known as a coulomb.

Gravitational pull (related to mass) and the applied electric field will exert forces on the droplet, causing qE to be directed upward and mg to be directed downward.
F = ma = qEo -mg = 0.

The equation becomes qEo = mg And , Eo = mg/q
Thus, only choice C is accurate.

Correct response.

Given:

d=0.5cm=0.005m

V = 0.6V

e = -1.6×10-19C

F=?

Answer:

E=v/d, as

60/0.005

= 12,000 V/m

E=12,000V/m, then

E=F/e now

F = eE

F = (1.6×10-19C)(12,000V/m)

F = 1.92×10-15N

Outcome:

F = 1.92×10-15N

A parallel plate capacitor’s capacitance is directly proportional to the dielectric constant (k) of the medium between the plates and the area of one of the plates (A). It also has an inverse relationship with the separation between the plates (d).

In terms of mathematics,

(εo is the free space permittivity, which has a value of 8.85 x 10-12 F/m).

Two charges exerting force on one another The distance r between q1 and q2 is proportional to q1 x q2 / r2.

Each capacitor in a parallel configuration receives the entire battery voltage. As a result, the potential difference across each capacitor is equal.