The following formula can be used to explain the motion of a basic harmonic oscillator:
a = -ω2 * x
where ω is the oscillator’s angular frequency, ‘a’ is the acceleration, and ‘x’ is the displacement.
The oscillator’s time period is determined by:
T = 2π/ω
where ‘T’ stands for the time frame.
The time frame in this instance is specified as 10 seconds. Thus, the angular frequency can be determined as follows:
ω = 2π/ T = 2π /10 =π/5
When this value of ω is entered into the equation of motion, we obtain:
a = -(π /5)2 * x
When we simplify, we obtain:
a = – (2π /10)2 * x
Consequently, choice C) is the right one: a = – (2π / 10)2 * x
The following formula can be used to explain the motion of a basic harmonic oscillator:
a = -ω2 * x
where ω is the oscillator’s angular frequency, ‘a’ is the acceleration, and ‘x’ is the displacement.
The oscillator’s time period is determined by:
T = 2π/ω
where ‘T’ stands for the time frame.
The time frame in this instance is specified as 10 seconds. Thus, the angular frequency can be determined as follows:
ω = 2π/ T = 2π /10 =π/5
When this value of ω is entered into the equation of motion, we obtain:
a = -(π /5)2 * x
When we simplify, we obtain:
a = – (2π /10)2 * x
Consequently, choice C) is the right one: a = – (2π / 10)2 * x