Generate Quiz 6A3579F6EA678

Charge/Time = Current
Charge/current = 5000/20 = Time

Time= 250 sec

I * r = V

Given:

E (the battery’s electromotive force, or emf) = 10 V

Vt (the battery’s terminal voltage) = 9 V

I, or the battery’s current, equals 1 A.

The voltage across the battery’s terminals when it is connected to an external circuit is known as the terminal voltage (Vt).

Vt = E – V_drop

To find the internal voltage drop, we can rewrite this equation:

E – Vt = V_drop

Replace the specified values with:

V_drop = 10 V minus 9 V

V_drop equals 1 V.

We can now determine the internal resistance (r) using Ohm’s law:

I * r = V_drop

1 V = 1 A * r

r = 1 V / 1 A

r = 1 ohm

Thus, the battery’s internal resistance is 1 ohm.

By adding the resistance, 3+2=5 ohms, one can determine the resistance of resistors connected in series.V=IR is the formula that links voltage, resistance, and current.

V = IR

(6) = (5)(I)

6/5 = I

= 1.2 Ohms.

Both R1=6Ω and R2=4Ω are resistances.

In the face of resistance, tolerance:

ΔR1 =.6Ω

ΔR2 =.4Ω

The combination’s overall resistance Req=R1+R2=6+4=10Ω

The equivalent resistance’s total tolerance is ΔReq=ΔR1+ΔR2=.6+.4=1Ω.

Therefore, the combination’s percentage tolerance is 1Ω/10Ω × 100 = 10%.

I/V = R

= 10/1

= 10Ω

V/R = I

= 8/10

= 0.8 A

Given:

V = 1.5V

l=5m

A = 2.5×10-7m²

Locate:

What is resistivity?

V = IR

V/I = R

R=resistivity×l/A

2=resistivity×5/2.5×10-7

Resistivity=1×10-7

The potential gradient has an inverse relationship with a potentiometer’s accuracy. A higher accuracy is indicated by a smaller potential gradient. We can decrease the potential gradient by lengthening the potentiometer wire because the two variables are inversely related. Consequently, the potentiometer’s accuracy rises.

A potentiometer is a device that compares an unknown voltage to a known reference voltage in order to measure voltage or the “potential difference.” Ohmmeters are used to measure resistance, and galvanometers and ammeters are used to measure current.

According to Ohm’s law, the voltage V applied to a conductor directly determines the current flowing through it; in other words, V = IR. This law does not apply to semiconductors or insulators; it only applies to conductors and resistors.