Generate Quiz 6A357BD7B9957

This is the right response. The gravitational pull between the satellite and the earth in a circular orbit is perpendicular to the satellite’s displacement. The definition of work in this context is the dot product of displacement and force. The earth’s work on the satellite is zero since the dot product of two perpendicular vectors is zero.

The force that the elevator floor applies to an object is its apparent weight, and this force is equal to the net force acting on the object.
Applying the equation Fnet = mg – ma

where m is the object’s mass.
g is the gravitational acceleration.
A is the elevator’s acceleration.
Since the elevator is traveling downward in this instance at an acceleration equal to the acceleration caused by gravity, a = g.
Therefore, Fnet = mg – ma = m(g – g) = 0.
Thus, the object’s apparent weight is zero. Option A is the right response.

The formula for gravitational force is F=GMm/R2.
where M is the mass of the earth, m is the mass of the object, R is the distance between the object and the center of the earth, and G is constant.

Force on the ground = GMm/R2
Since distance is equal to the earth’s radius
Within the specified orbit, Force=GMm/(R+R/50)We obtain 51R/50 GMm/(51R/50) by taking the LCM of R+R/50.2500/2601R2500 = GMmx2500/2601R2500
Combining these two equations:
GMm/R2 = GMm x 2500/2601R²
After canceling all of the constants, we will be left with
0.96W = 2500/2601.
Thus, choice D will be the correct one.

The mass of the earth is 5.98 x 10^24 kg, which is determined by equating Newton’s second law with his law of universal gravitation and entering the experimentally confirmed acceleration value of 9.8 m/s2.
It can only have one answer because it is numerically derived.

A solar day is the interval of time between two successive sun appearances. Therefore, the original definition of the mean second, which serves as the fundamental unit of time, was (1/60) (1/60) (1/24) of a mean solar day. Universal time is the term used to describe the earth’s rotation around its axis.

In the case of free falling, the body’s acceleration is independent of its mass. As a result, the ball and boy accelerate at the same rate. Their velocities would therefore be the same everywhere. “Relative” velocity is therefore zero. As a result, the ball will perceive the boy as remaining motionless.

The gravitational law states:

F = G m1m2/r2

F = (6.674x 10^-11)(10)(10)(1)2.

F = 667.4x 10^-11 N

Option E is the right one.

Because this is a theoretical question, choices A, B, C, and D are all wrong.

The centripetal force for a satellite is provided by gravity; thus:

\where Fg is the centripetal force and Fc is the gravitational force} Fg=Fc

GMm/r2=mv2/r

Put R at the center of the equation to get:

r=[GMT2/4×2]⅓

The centripetal force required to maintain the satellite’s circular motion is supplied by the satellite’s gravitational pull. The following formula provides the gravitational force between Earth and the satellite:

F = G(Mm)/r2

The universal gravitational constant is denoted by G.

Given that the centripetal force is provided by gravity, we have:

F = mv2/r

When we combine the two equations above, we obtain:

G(Mm)/r2 = mv2/r

When we simplify this equation, we obtain:

v2 = GM/r

Consequently, v2 = GM/r gives the speed of a satellite in a circular orbit with radius r around the Earth.

The force of gravity acting on an object is its weight, which is determined by multiplying its mass by the acceleration of gravity, or w = mg. Because it has no effect on the person’s mass or gravitational acceleration, this remains unchanged when the elevator is moving.