Generate Quiz 6A875BE9E7DED

Regarding identifying the acceleration’s direction:

1. Acceleration occurs in the direction of movement when speeding up.

2. The acceleration is opposite to the direction of movement when reducing speed.

Therefore, the acceleration in the westward direction will be opposite to the acceleration in the eastward direction.

The tension force is the force acting in opposition to the body weight of the object fastened to the string.

The rate at which an object’s velocity changes in relation to time is called acceleration. It is calculated by dividing the velocity change by the time it takes for the change to occur. The SI unit of acceleration is meter per second per second (m/s2) since the SI unit of velocity is meter per second (m/s) and the SI unit of time is second (s).

When the acceleration is zero or the velocity is constant, the instantaneous velocity can equal the average velocity because all of the instantaneous velocities will be equal to the average velocity and to each other. Alternatively, the distance-time graph will be a straight line with constant velocity at each point.

vi =4m/s

vf =14m/s

t =3sec

m=1200kg

v=8m/s

d=16m

v2=u2+2as

(8)2=(0)2+2(a)(16)

64=32a

a=2m/s2

F = ma

= 1200×2

=2400N

The ratio of the normal force pressing two surfaces together to the frictional force preventing them from moving is known as the coefficient of friction. Typically, the Greek letter mu (μ) is used to represent it. In mathematics, μ is equal to F/N, where N is the normal force and F is the frictional force.

F=ma is Newton’s second law of motion. When F=μN is used to equate this equation

μN = ma, where N = mg

Where m will be eliminated on both sides of the equation, μmg=ma

μg = a

0.2 x 10 = a

a = 2 m/s^2.

u = 10 m/s and a = 2 m/s^2.

motion equation

V2 = u2 + 2as

0 = 102 + 2 x 2 x s

0 = 100 + 4s

S = 100/4

S = 25 m

Distance is always positive.

Because the curve’s slope is constant, the particle’s acceleration is also constant.

At t=10 seconds, the particle reverses direction.

Because the area above and below the x-axis is not equal, the particle has non-zero displacement.

Therefore, A is right.