Generate Quiz 6A91CE0A9E5BD

Na2CO3 = 23(2)+12+16(3) = 46+12+48 = 106

Using given mass divided by molar mass, concentration

1M is the concentration (106/106).

This is the right choice as the principle quantum number provides information about the energy levels or shells.

The wavelength of X-rays, which is dependent on frequency, determines their penetration power. Longer wavelength X-rays have a lower frequency, which means they have less energy. They are referred to as soft X-rays because of their lower penetration power. On the other hand, shorter wavelength X-rays, also known as hard or highly penetrating X-rays, have a stronger penetrating power.

The form of an atom’s orbital is determined by the Azimuthal quantum number (l).When n is the principal quantum number, the azimuthal quantum number can have integer values between 0 and (n – 1).

However, because the values of l must adhere to specific constraints based on the principal quantum number (n), the azimuthal quantum number (l) in a 2d orbital cannot equal 2. For a given n, the permitted values of l range from 0 to (n – 1).

For instance:

The only permitted value for l when n = 1 is 0.
The permitted values for l when n = 2 are 0 and 1.
The permitted values for l when n = 3 are 0, 1, and 2.

The spin quantum number, which is not a direct result of the Schrodinger equation, characterizes the intrinsic angular momentum or spin of an electron.

The behavior of particles in terms of their positions and momenta is accurately described by the Schrodinger equation. Another quantum property is spin, which has no effect on particle position or momentum that would necessitate its inclusion in the equation.

is accurate since electrons have a fixed angular momentum as they orbit the nucleus, and their positions are indicated by quantum numbers.

The formula for the yield percentage is:

Actual yield divided by theoretical yield times 100% is the percent yield.

The actual yield divided by the theoretical yield and multiplied by 100 is the yield percentage.

The amount of a product that comes from a chemical reaction is known as the actual yield. The amount of product that could be produced from a reaction, on the other hand, if every reactant turns into product, is known as the calculated or theoretical yield.

One mole of oxygen gas (O2) has a mass of 16+16 = 32g/mol.

There are 6.02×1023 molecules in 1 mole of oxygen gas.

So, to find out the mass of one molecule of O2, we need to divide 32g by 6.02×1023.

B is therefore the right choice.

Since there was no calculator available for the exam, this answer should be learned. Working is displayed below:-

Electron charge: -1.602 x 10^-19 C

Electron mass: 9.11 x 10^-31 kg

Electrons in 1kg: 1/(9.11 x 10^-31) = 1.10 x 10^30

Charge of 1kg of electrons: (1.10 x 10^30)(-1.602 x 10^-19) = -1.76 x 10^11 C

Bohr came up with the formula for the radius of a hydrogen atom’s nth orbit. Bohr used fundamental physics to determine the formula for the hydrogen spectrum in accordance with his theory of the hydrogen atom.

Mg+2 = 12- 2 = 10 Na+ = 11-1 = 10

Both have ten electrons as a result.

In general, the term “percent yield” is used. To calculate this, divide the quantity of the product by the quantity of the ‘limiting’ reactant (the one that is present in the least amount), and then multiply the result by 100.

B) 14 is the appropriate choice.

We must ascertain the electron configuration of an element with an atomic number of 26 in order to calculate the number of electrons in its M-shell.

Iron (Fe) is the element with atomic number 26. Iron’s electron configuration is:

3s² 3p⁶ 4s² 3d⁶ 1s² 2s² 2p⁶

All of the lower energy levels (shells) will be filled before the M-shell in the ground state. Consequently, the third shell (n=3) is represented by the M-shell. The 3s, 3p, and 3d subshells make up the M-shell.

A maximum of two electrons can be contained in the 3s subshell, six electrons in the 3p subshell, and ten electrons in the 3d subshell.

The right choice is ‘C’ since 4s is the outermost shell of a neutral atom with one electron in 3d and 4s has two electrons.

The electronic configuration of Cu is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰.
Copper loses the 4s¹ electron when it sheds one electron to create the Cu+1 ion. Consequently, 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰, or [Ar][3d10], is the electronic configuration of Cu+1.

Elements’ ionic radii follow the same pattern as their atomic radii. For the elements of the second period, the atomic size typically decreases over time. The reason for this is that the outer electrons in the period are in the same valence shell, and as the atomic number rises, the effective nuclear charge rises as well, increasing the electrons’ attraction to the nucleus. Because adding one or more electrons would increase electron repulsion and decrease effective nuclear charge, the size of an anion will be larger than that of the parent atom.

Options A and C in the given question are cations for the second period. As a result, their ionic radius will be smaller than that of anions of the same period.

A nodal plane is the area where there is a very small chance of discovering an electron. A nodal plane is an area of space where there is no chance of finding an electron passing through a nucleus.

Option ‘B’ is accurate since the image provided does not break any rules and accurately depicts how nitrogen’s valence electrons are arranged in their respective orbitals in accordance with the electronic configuration of nitrogen, as seen in the image below:

The formula moles = mass / molecular mass will be applied.

Molar mass of Ag2CO3= 275g/mol

There are 8.694 moles.

Mass = moles x molar mass

Mass = 8.694 x 275 = 2390g

The reactant that is consumed first in a chemical reaction and thus restricts the amount of product that can be produced is known as the limiting reactant (or limiting reagent).

The addition of protons causes the nuclear charge to gradually increase over time. The negatively charged electrons are more strongly attracted to this.

The empirical formula’s molecular mass is 2(12.1) + 2(1) + 16 = 42.2.

We must now locate ‘n’

The average of the specified range of 160–170 is the experimental molecular weight, which is 165.

We can determine n by

n = (empirical formula mass) / (experimental molecular weight)

= 165/42.2 = 3.9

Therefore, “n” is roughly 4.

Now, 4C2* 4H2* O4 = C8H8O4

Option C is therefore the right choice.

Since each student needs 10 g of NaOH, 42 students will need the following total amount of NaOH:

420 g (10 g/student x 42 students).

909 g of NaOH are initially present in the container. Consequently, following the experiment, the amount of NaOH that remains is:

909 g – 420 g = 489 g

Grams to kilograms conversion:

489 g = 0.489 kg

Therefore, D) 0.489 kg is the right response.

Sulfur has the electronic configuration [Ne]3s² 3p⁴. Sulfur (S) has 16 electrons, and the electron distribution of this configuration is 1s² 2s² 2px² 2py² 2pz² 3s² 3px² 3py¹ 3pz¹. S is the right response as a result.