Silver oxide decomposes when heated to silver and oxygen. If 0.5 moles of lunar caustic is heated up to 450 degrees, giving out nitrogen dioxide and oxygen leaving silver as metal, what is the mass of the residue?
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Silver nitrate is broken down to produce silver, nitrogen dioxide, and oxygen gas. The balanced chemical equation for silver nitrate’s breakdown is as follows:
2AgNO3 → 2Ag + 2NO2 + O2
We obtain from a balanced chemical equation:
Two moles of Ag are produced from two moles of lunar caustic (AgNO3).
Thus, 0.5 moles of Ag will be produced from 0.5 moles of lunar caustic.
Mass/molar mass = moles
mass = molar mass * moles
0.5 * 107.8 = mass
mass = 53.9 or 54 g.
Silver nitrate is broken down to produce silver, nitrogen dioxide, and oxygen gas. The balanced chemical equation for silver nitrate’s breakdown is as follows:
2AgNO3 → 2Ag + 2NO2 + O2
We obtain from a balanced chemical equation:
Two moles of Ag are produced from two moles of lunar caustic (AgNO3).
Thus, 0.5 moles of Ag will be produced from 0.5 moles of lunar caustic.
Mass/molar mass = moles
mass = molar mass * moles
0.5 * 107.8 = mass
mass = 53.9 or 54 g.