Generate Quiz 6A92E7758E7B0

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At first, the car’s weight was equal to m1 = 1000 kg.

Initial vehicle velocity = v1 = 50 km/h

After the mass is placed on it, the weight is equal to m2 = 1000 + 250 kg.

The car’s final velocity = v2 =?

Applying the conservation of momentum law:

Initial momentum equals final momentum.

m1 v1 = m2 v2

1000 kg x 50 km/h = 1250 kg x v2

50,000 kg km/h / 1250 kg = v2

5000 / 125 = 200 / 5 = 40 km/h = v2

The vector sum of F1 and F2 should be equal in magnitude and opposite in direction to the vector F3 if the frictional force F3 balances the forces F1 and F2.

The vectors that represent F1 and F2 should, in terms of a triangle, form a closed triangle, with the resulting vector (sum of vectors) pointing in the opposite direction of F3.

Option C is therefore accurate.

Option B is accurate because a projectile’s horizontal velocity is constant, meaning it never changes. Gravity causes a vertical acceleration of 9.8 ms-2, downward, which causes a projectile’s vertical velocity to change by 9.8 m/s every second.

When the angle is expressed in degrees, calculating the arc length

We are aware that s = rθ gives the length of an arc when θ is expressed in radians. Assume that θ is expressed in degrees.

Speed is equal to the distance-time graph’s slope.

Graph (I) has a constant slope. Speed is therefore constant.

In order to answer these questions, the variables on the x and y-axes must be examined.

The clockwise and anticlockwise moments of the rod must coincide for it to be balanced.

5×50 = 10×x

x = 25 cm 50 + 25 = 75 cm.

250/10 = x

There is only one possible response because it is a numerical question.

It is possible to analyze projectile motion by dividing it into vertical and horizontal components. There is no horizontal acceleration and a projectile’s horizontal velocity stays constant during its trajectory when there is no air resistance.

Because gravity affects a projectile’s vertical motion, the vertical acceleration remains constant during the motion. Nevertheless, the projectile’s vertical velocity drops to zero at the trajectory’s highest point before veering off course and beginning to descend. Consequently, during the trajectory, neither the vertical velocity nor the total velocity is ever zero.

Therefore, the horizontal acceleration is the only quantity that remains constant at zero throughout the projectile’s trajectory.

Power=Energy/time

Energy=power ×time

60 watt×120 sec =7200 J =7.2 kilo J.

There are two forces at work on a mass m hanging from a string in an elevator:

tension in the string (T) and the gravitational force (m g). Newton’s second law provides the net force (F net) acting on the mass:

F net = m a

The difference between the tension (T) and the gravitational force (m g) in this instance is the net force:

T − m g = m a

T = m g − m an is the result of solving for T.

The provided vector’s magnitude is:

|0.8i + 0.5j + ck| = √(0.8² + 0.5² + c²)

The magnitude of the given vector must be 1 in order for it to be a unit vector. Thus,

√(0.8² + 0.5² + c²) = 1

0.64 + 0.25 + c² = 1

c² = 1 – 0.64 – 0.25 = 0.11

c= √0.11

Consequently, c has a value of √0.11, or roughly 0.33.

Therefore, E is the right response.

Newton’s third law of motion will be followed by the two bodies in contact. Every action has an equal and opposite reaction, according to the third law. The reaction forces of the two bodies will be felt in opposing directions.

The right answer is 91 meters. Calculus, which is required for the solution, is unfamiliar to the majority of pre-medical students. It is very unlikely that someone will ask this kind of question.)

The answer is as follows:

A body’s mass is a quantitative indicator of its inertia. An object’s resistance to changing its motion is known as its inertia. It is an object’s propensity to either stay at rest or continue traveling in a straight line at a steady speed absent an outside force.

|R1| = 4 ; |R2| = 3 θ1 = 30° ; θ = 90°

The vector product now,..

|R1 × R2 |= |R1| |R2| (sin θ2 – θ1)

= 4 × 3 × sin (90° – 30°) = 4 × 3 × √3/2

|R1 × R2 | = 6√3 cm

Along the Z-axis is this vector.

We’ll apply the following formulas:

Because they provide incorrect numerical values, options A, B, and C are all incorrect.

A straight line with a non-zero slope represents the displacement time graph for uniform motion.

Acceleration is indicated by the v-t graph’s slope. The acceleration would be infinite if the slope was parallel to the y-axis, meaning that the velocity would skyrocket with no change in time.

In terms of mathematics,

Slope = ∆y / ∆x = ∆v / ∆t = a

since ∆t = 0.

a = ∆v / 0.

a = inifinity

The laws of physics, particularly the principle of inertia, apply to the mud on a bicycle tire when it is in motion. According to the law of inertia, unless an outside force acts upon an object, it will continue to move in the same direction or remain at rest.

Because of its inertia, the mud on the bicycle tire wants to keep going in the same direction as the tire moves forward. Nevertheless, the tire limits it. Because the tire is rolling, the point of contact between it and the ground is momentarily at rest (in relation to the tire). As a result, when the tire leaves the ground, the mud is thrown off in a direction tangent to the tire.

Displacement (Δx) = Final position (xf) – Initial position (xi)
Coordinates in a coordinate system, such as the distance traveled in a straight line or a change in position in two or three dimensions, can be used to represent the final position (xf) and the initial position (xi).

xf=8 sec xi=4 sec – 2 sec

Δx = 50 – 25 = 25

Therefore, 25 meters is the answer.